FastPrepCount Numbers with an Even Digit Count

Count Numbers with an Even Digit Count

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Problem statement

Given an array of positive integers numbers, count how many values have an even number of decimal digits.

Return that count.

Function

countEvenDigitNumbers(numbers: int[]) → int

Examples

Example 1

numbers = [12, 134, 111, 1111, 10]return = 3

The values 12, 1111, and 10 have two, four, and two digits, respectively.

Example 2

numbers = [1, 10, 999, 1000, 10000]return = 2

Only 10 and 1000 have an even number of digits.

Constraints

  • 1 <= numbers.length <= 1000
  • 1 <= numbers[i] <= 10^4

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public int countEvenDigitNumbers(int[] numbers) {
    // Write your code here.
}
numbers[12, 134, 111, 1111, 10]
expected3
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