FastPrepCompare Odd- and Even-Index Sums

Compare Odd- and Even-Index Sums

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Problem statement

You are given an integer array values. Using zero-based indices, compute the sum at even indices and the sum at odd indices.

Return "odd" when the odd-index sum is larger, "even" when the even-index sum is larger, and "equals" when the sums are equal.

Function

compareIndexSums(values: int[]) → String

Examples

Example 1

values = [1,2,3,4]return = "odd"

The even-index sum is 4 and the odd-index sum is 6.

Example 2

values = [5,1,0,4]return = "equals"

Both index groups sum to 5.

Constraints

  • 0 <= values.length <= 100000
  • -100000 <= values[i] <= 100000

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public String compareIndexSums(int[] values) {
    // Write your code here.
}
values[1,2,3,4]
expected"odd"
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