FastPrep
Problem · String

IPv4 Forward Iterator

Learn this problem
● EasyOpenAIFULLTIMEPHONE SCREEN

Problem statement

You are given an IPv4 address as a dotted-decimal string. Starting at that address, visit every IPv4 address in increasing numeric order until 255.255.255.255 is reached.

The starting address and 255.255.255.255 are both included. Incrementing an address carries across octets, so the address after 10.0.0.255 is 10.0.1.0.

Interview context

The phone-screen version asked candidates to implement a Python IPV4Iterator with __init__, __iter__, and __next__. It began at the supplied address and yielded every address through the IPv4 upper bound. This function returns the exact finite sequence that iterator would yield.

Function

iterateIPv4Forward(startIp: String) → String[]

Examples

Example 1

startIp = "255.255.255.253"return = ["255.255.255.253", "255.255.255.254", "255.255.255.255"]

The final octet advances twice before the maximum IPv4 address is reached.

More OpenAI problems

drafts saved locally
public String[] iterateIPv4Forward(String startIp) {
  // write your code here
}
startIp"255.255.255.253"
expected["255.255.255.253", "255.255.255.254", "255.255.255.255"]
checking account