FastPrep
Problem · String

Odd One Out

Learn this problem
● EasyMathWorks logoMathWorksINTERNOA

Problem statement

Analyze the difference in adjacent letters of the alphabet given a string. Given an input sequence of words, find the 'Odd One Out' by checking the difference between adjacent letters. The element having a distinct difference is the 'Odd One Out.'

Function

findOdd(series: String[]) → String

Complete the function findOdd in the editor.

findOdd has the following parameter(s):

  1. string series[n]: an array of strings

Returns

string: the odd one out.

Examples

Example 1

series = ["ACB", "BDC", "CED", "DEF"]return = "DEF"

In the first three strings, the differences between the letters are (+2, -1), e.g. 'C' - 'A' = 2, 'B' - 'C' = -1. In the last string, the differences are (+1, +1). "DEF" is the odd one out.

Constraints

  • 3 ≤ n ≤ 26
  • 2 ≤ length of series[i] ≤ 26
  • All strings are uppercase English letters only.
  • Within a test case, all strings are of equal length.

More MathWorks problems

drafts saved locally
public String findOdd(String[] series) {
  // write your code here
}
series["ACB", "BDC", "CED", "DEF"]
expected"DEF"
checking account