Problem · Hash Table
Worker Management, Part 2: Top Workers
Learn this problemProblem statement
Continue the worker management system from Part 1. ADD_WORKER, REGISTER, and GET keep the same behavior.
New Operation
["TOP_N_WORKERS", n, position]: return up tonworkers whose current position equalsposition.- Rank by total time from completed office sessions in descending order, then by worker ID in ascending alphabetical order.
- Format the result as
workerId1(time1), workerId2(time2), .... - A worker with no completed session has time
0. Return an empty string when no worker has the requested position.
Function
workerManagementLevel2(operations: String[][]) → String[]Examples
Example 1
operations = [["ADD_WORKER","John","Junior Developer","120"],["ADD_WORKER","Jason","Junior Developer","120"],["ADD_WORKER","Ashley","Junior Developer","120"],["REGISTER","John","100"],["REGISTER","John","150"],["REGISTER","Jason","200"],["REGISTER","Jason","250"],["REGISTER","Jason","275"],["TOP_N_WORKERS","5","Junior Developer"],["TOP_N_WORKERS","1","Junior Developer"],["REGISTER","Ashley","400"],["REGISTER","Ashley","500"],["REGISTER","Jason","575"],["TOP_N_WORKERS","3","Junior Developer"],["TOP_N_WORKERS","3","Middle Developer"]]return = ["true","true","true","registered","registered","registered","registered","registered","Jason(50), John(50), Ashley(0)","Jason(50)","registered","registered","registered","Jason(350), Ashley(100), John(50)",""]Jason and John initially tie at 50, so Jason comes first alphabetically. Jason's session from 275 to 575 later raises his total to 350.
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