FastPrepMerge Intervals

Merge Intervals

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Problem statement

Given an array of closed intervals where intervals[i] = [start_i, end_i], merge every pair of overlapping intervals.

Return the non-overlapping intervals that cover every input interval, sorted by start value. Intervals that share an endpoint are considered overlapping.

Function

mergeIntervals(intervals: int[][]) → int[][]

Examples

Example 1

intervals = [[1,3],[2,6],[8,10],[15,18]]return = [[1,6],[8,10],[15,18]]

Intervals [1,3] and [2,6] overlap, so they merge into [1,6].

Example 2

intervals = [[1,4],[4,5]]return = [[1,5]]

The intervals share endpoint 4, so they merge.

Example 3

intervals = [[8,10],[1,4],[2,3],[15,18],[6,9],[3,7],[17,20],[12,12]]return = [[1,10],[12,12],[15,20]]

After sorting, the first five intervals form one overlap chain. The point interval remains separate, and the last two intervals merge.

Constraints

  • 1 <= intervals.length <= 10000
  • intervals[i].length == 2
  • 0 <= start_i <= end_i <= 10000

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public int[][] mergeIntervals(int[][] intervals) {
  // write your code here
}
intervals[[1,3],[2,6],[8,10],[15,18]]
expected[[1,6],[8,10],[15,18]]
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