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Apply Binary State Operations

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Problem statement

You have a binary state array of length n, initially filled with 0. Apply the strings in operations in order:

"L": find the leftmost state equal to 0 and change it to 1. If no zero remains, do nothing.
"Cj": change the state at zero-based index j to 0, regardless of its current value. The index may contain multiple digits.

Return the final state as a string of 0 and 1 characters.

Function

applyBinaryStateOperations(n: int, operations: String[]) → String

Examples

Example 1

n = 8operations = ["L","L","C1","C6","L"]return = "11000000"

The first two operations set indices 0 and 1. C1 clears index 1, C6 leaves an existing zero unchanged, and the final L sets index 1 again.

Example 2

n = 4operations = ["L","L","L","C0","L"]return = "1110"

Three loads produce 1110. Clearing index 0 produces 0110, and the last load selects index 0 again.

Constraints

1 <= n <= 10⁵
1 <= operations.length <= 10⁵
Every operation is either "L" or "Cj" for an index 0 <= j < n.