Elements Occurring More Than n/3 Times
Problem statement
Given an integer array nums of length n, return every distinct value whose frequency is strictly greater than n / 3.
Return qualifying values in increasing numerical order. Frequency counts occurrences of the whole integer value, rather than its individual decimal digits. Return an empty array if no value qualifies.
Function
majorityOverThird(nums: int[]) → int[]Examples
Example 1
nums = [3,2,3]return = [3]The value 3 occurs twice, strictly more than 3 / 3 = 1.
Example 2
nums = [1,2,1,2,1,2,3]return = [1,2]Both 1 and 2 occur three times, more than 7 / 3.
Example 3
nums = [1,2,3,4]return = []No frequency exceeds 4 / 3.
Constraints
0 <= nums.length <= 10^5-10^9 <= nums[i] <= 10^9- For integer frequencies, the threshold is equivalent to
frequency > floor(n / 3).